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UPDATE
use_services2animal
SET service_price = t.price
FROM use_services2animal c
INNER JOIN doctor_service_price t
ON c.service_id = t.service_id
where t.doctor_id = 1;
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UPDATE
use_services2animal
SET service_price = t.price
FROM use_services2animal c
INNER JOIN doctor_service_price t
ON c.service_id = t.service_id
where t.doctor_id = 1;
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UPDATE use_services2animal
SET service_price = doctor_service_price.price
FROM doctor_service_price
WHERE use_services2animal.service_id = doctor_service_price.service_id and doctor_service_price.doctor_id = 1;
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$query->select("FIELD(column.id, 1,2)>0 as is_column")
FIELD(column.id, `1`, `2)>0` AS `is_column`
Подскажите, как убрать такую обработкуA
$query->select("FIELD(column.id, 1,2)>0 as is_column")
FIELD(column.id, `1`, `2)>0` AS `is_column`
Подскажите, как убрать такую обработкуЖ
TS
TS
$query->select("FIELD(column.id, 1,2)>0 as is_column")
FIELD(column.id, `1`, `2)>0` AS `is_column`
Подскажите, как убрать такую обработку$query->select("FIELD(
[[column.id
]], 1,2)>0 as is_column")
, или, как подсказывали, $query->select(
new Expression("FIELD(column.id, 1,2)>0 as is_column"
))VS
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A
A