R
Size: a a a
2021 February 02
nx
Пайтон очень легкий язык программирования. Я когда то перешел с с++, на пайтон и это было очень легко, хотя не привичный синтаксис, но теперь с пайтон на с++ х*й перейдешь
Говори за себя, дружок. Легко перешел на C# и C++ с Python
RQ
легко перешел с Python на перфокарты
К
легко перешел с Python на перфокарты
Слабак! Я с кубитов перешёл на морзянку!
C
gcc lab1.c lab1_helper.c -o lab1
lab1.c:
lab1.c:
RQ
Был в Египте, читал надписи на пирамиде после Python
C
Cyber Security
gcc lab1.c lab1_helper.c -o lab1
lab1.c:
lab1.c:
#include <stdio.h>
#include <stdlib.h>
#include "lab1_helper.h"
/*
* Calculates the sum of consecutive numbers from
* to
* Parameters:
* start - an integer defining the starting value of the series
* end - an integer defining the stopping point of the series.
*
* Return: the total summation
*
*/
long int arithmeticSum(long int start, long int end) {
long int total = 0;
for (long int i = start; i < end; i++) {
total += i;
}
return total;
}
/*
* Takes in two integers as input.
* Calculates the arithmetic sum between those to integers.
* Mallocs an integer array, and writes the two integer inputs to the array.
*
* If the program doesn't receive exactly 2 arguments as input,
* the program should print "Invalid number of arguments.\n", and then exit with
* error code
*
*/
int main(int argc, char* argv[]) {
long int arg1 = strtol(argv[1], 0, 0);
long int arg2 = strtol(argv[2], 0, 0);
long int sum = arithmeticSum(arg1, arg2);
printf("Arithmetic Sum between %d and %d is: %d.\n", arg1, arg2, sum);
long int* arr = malloc(1000 * sizeof(int));
*(arr ) = 0;
*(arr + 1) = 100;
free(arr);
printf("Malloc'd data for arg1 %li and %li .\n", arr[0], arr[1]);
return 0;}
#include <stdlib.h>
#include "lab1_helper.h"
/*
* Calculates the sum of consecutive numbers from
start* to
end (not including `end`).* Parameters:
* start - an integer defining the starting value of the series
* end - an integer defining the stopping point of the series.
*
* Return: the total summation
*
*/
long int arithmeticSum(long int start, long int end) {
long int total = 0;
for (long int i = start; i < end; i++) {
total += i;
}
return total;
}
/*
* Takes in two integers as input.
* Calculates the arithmetic sum between those to integers.
* Mallocs an integer array, and writes the two integer inputs to the array.
*
* If the program doesn't receive exactly 2 arguments as input,
* the program should print "Invalid number of arguments.\n", and then exit with
* error code
1.*
*/
int main(int argc, char* argv[]) {
long int arg1 = strtol(argv[1], 0, 0);
long int arg2 = strtol(argv[2], 0, 0);
long int sum = arithmeticSum(arg1, arg2);
printf("Arithmetic Sum between %d and %d is: %d.\n", arg1, arg2, sum);
long int* arr = malloc(1000 * sizeof(int));
*(arr ) = 0;
*(arr + 1) = 100;
free(arr);
printf("Malloc'd data for arg1 %li and %li .\n", arr[0], arr[1]);
return 0;}
C
Cyber Security
#include <stdio.h>
#include <stdlib.h>
#include "lab1_helper.h"
/*
* Calculates the sum of consecutive numbers from
* to
* Parameters:
* start - an integer defining the starting value of the series
* end - an integer defining the stopping point of the series.
*
* Return: the total summation
*
*/
long int arithmeticSum(long int start, long int end) {
long int total = 0;
for (long int i = start; i < end; i++) {
total += i;
}
return total;
}
/*
* Takes in two integers as input.
* Calculates the arithmetic sum between those to integers.
* Mallocs an integer array, and writes the two integer inputs to the array.
*
* If the program doesn't receive exactly 2 arguments as input,
* the program should print "Invalid number of arguments.\n", and then exit with
* error code
*
*/
int main(int argc, char* argv[]) {
long int arg1 = strtol(argv[1], 0, 0);
long int arg2 = strtol(argv[2], 0, 0);
long int sum = arithmeticSum(arg1, arg2);
printf("Arithmetic Sum between %d and %d is: %d.\n", arg1, arg2, sum);
long int* arr = malloc(1000 * sizeof(int));
*(arr ) = 0;
*(arr + 1) = 100;
free(arr);
printf("Malloc'd data for arg1 %li and %li .\n", arr[0], arr[1]);
return 0;}
#include <stdlib.h>
#include "lab1_helper.h"
/*
* Calculates the sum of consecutive numbers from
start* to
end (not including `end`).* Parameters:
* start - an integer defining the starting value of the series
* end - an integer defining the stopping point of the series.
*
* Return: the total summation
*
*/
long int arithmeticSum(long int start, long int end) {
long int total = 0;
for (long int i = start; i < end; i++) {
total += i;
}
return total;
}
/*
* Takes in two integers as input.
* Calculates the arithmetic sum between those to integers.
* Mallocs an integer array, and writes the two integer inputs to the array.
*
* If the program doesn't receive exactly 2 arguments as input,
* the program should print "Invalid number of arguments.\n", and then exit with
* error code
1.*
*/
int main(int argc, char* argv[]) {
long int arg1 = strtol(argv[1], 0, 0);
long int arg2 = strtol(argv[2], 0, 0);
long int sum = arithmeticSum(arg1, arg2);
printf("Arithmetic Sum between %d and %d is: %d.\n", arg1, arg2, sum);
long int* arr = malloc(1000 * sizeof(int));
*(arr ) = 0;
*(arr + 1) = 100;
free(arr);
printf("Malloc'd data for arg1 %li and %li .\n", arr[0], arr[1]);
return 0;}
#include "lab1_helper.h"
void helperFunction(int a, int b) {
printf("This is a *REALLY* important helper function 🎉🎉.\na: %d\nb: %d\n", a, b);
}
void helperFunction(int a, int b) {
printf("This is a *REALLY* important helper function 🎉🎉.\na: %d\nb: %d\n", a, b);
}
C
почему оутпут сегментэйшн фаулт?
MR
Был в Египте, читал надписи на пирамиде после Python
😄 .
C
Cyber Security
#include "lab1_helper.h"
void helperFunction(int a, int b) {
printf("This is a *REALLY* important helper function 🎉🎉.\na: %d\nb: %d\n", a, b);
}
void helperFunction(int a, int b) {
printf("This is a *REALLY* important helper function 🎉🎉.\na: %d\nb: %d\n", a, b);
}
lab1_helper.h
MR
Cyber Security
#include <stdio.h>
#include <stdlib.h>
#include "lab1_helper.h"
/*
* Calculates the sum of consecutive numbers from
* to
* Parameters:
* start - an integer defining the starting value of the series
* end - an integer defining the stopping point of the series.
*
* Return: the total summation
*
*/
long int arithmeticSum(long int start, long int end) {
long int total = 0;
for (long int i = start; i < end; i++) {
total += i;
}
return total;
}
/*
* Takes in two integers as input.
* Calculates the arithmetic sum between those to integers.
* Mallocs an integer array, and writes the two integer inputs to the array.
*
* If the program doesn't receive exactly 2 arguments as input,
* the program should print "Invalid number of arguments.\n", and then exit with
* error code
*
*/
int main(int argc, char* argv[]) {
long int arg1 = strtol(argv[1], 0, 0);
long int arg2 = strtol(argv[2], 0, 0);
long int sum = arithmeticSum(arg1, arg2);
printf("Arithmetic Sum between %d and %d is: %d.\n", arg1, arg2, sum);
long int* arr = malloc(1000 * sizeof(int));
*(arr ) = 0;
*(arr + 1) = 100;
free(arr);
printf("Malloc'd data for arg1 %li and %li .\n", arr[0], arr[1]);
return 0;}
#include <stdlib.h>
#include "lab1_helper.h"
/*
* Calculates the sum of consecutive numbers from
start* to
end (not including `end`).* Parameters:
* start - an integer defining the starting value of the series
* end - an integer defining the stopping point of the series.
*
* Return: the total summation
*
*/
long int arithmeticSum(long int start, long int end) {
long int total = 0;
for (long int i = start; i < end; i++) {
total += i;
}
return total;
}
/*
* Takes in two integers as input.
* Calculates the arithmetic sum between those to integers.
* Mallocs an integer array, and writes the two integer inputs to the array.
*
* If the program doesn't receive exactly 2 arguments as input,
* the program should print "Invalid number of arguments.\n", and then exit with
* error code
1.*
*/
int main(int argc, char* argv[]) {
long int arg1 = strtol(argv[1], 0, 0);
long int arg2 = strtol(argv[2], 0, 0);
long int sum = arithmeticSum(arg1, arg2);
printf("Arithmetic Sum between %d and %d is: %d.\n", arg1, arg2, sum);
long int* arr = malloc(1000 * sizeof(int));
*(arr ) = 0;
*(arr + 1) = 100;
free(arr);
printf("Malloc'd data for arg1 %li and %li .\n", arr[0], arr[1]);
return 0;}
смотря на этот синтаксис отфильтровываю лишний текст😂
MM
Был в Египте, читал надписи на пирамиде после Python
После питона научился читать мед.справки
ЕЖ
Еще есть?
)))😁👍🏼
RQ
Единственно что нелегко иногда из-за типизации, тайпинги тоже не очень
Типизация - это одно из лучших, что произошло с питоном. В ПХП нравится типизация