MK
$ perl
print(`ls`)^D
README.md
assets
babel.config.js
distSize: a a a
2020 June 02
SS
$ perl
print(`ls`)^D
README.md
assets
babel.config.js
distНу вот ты и спалился фронтендер
MK
MK
не хаскелем же вас пугать
2020 June 03
DS
Есть кто разбирается в conda и ее пакетах? есть pyproject.toml и желание как то сбилдить пакеты конда и загрузить в артефактори у заказчика. Начитался про meta.yaml, попробовал сбилдить, но как то не пошло
2020 June 04
Б
There are a lot of ways to merge two dicts:
1. Long but simple:
2. Unpacking (keys must be strings):
3. Unpacking again:
4.
In python 3.9, PEP-584 introduced the 5th way. Meet the
Basically, that's the same as the first way but shorter and can be inlined.
1. Long but simple:
merged = d1.copy()
merged.update(d2)
2. Unpacking (keys must be strings):
merged = {**d1, **d2}3. Unpacking again:
merged = dict(d1, **d2)
4.
collections.ChainMap. Result isn't dict but so.In python 3.9, PEP-584 introduced the 5th way. Meet the
| operator for dict!merged = d1 | d2
Basically, that's the same as the first way but shorter and can be inlined.
Б
There are a lot of ways to merge two dicts:
1. Long but simple:
2. Unpacking (keys must be strings):
3. Unpacking again:
4.
In python 3.9, PEP-584 introduced the 5th way. Meet the
Basically, that's the same as the first way but shorter and can be inlined.
1. Long but simple:
merged = d1.copy()
merged.update(d2)
2. Unpacking (keys must be strings):
merged = {**d1, **d2}3. Unpacking again:
merged = dict(d1, **d2)
4.
collections.ChainMap. Result isn't dict but so.In python 3.9, PEP-584 introduced the 5th way. Meet the
| operator for dict!merged = d1 | d2
Basically, that's the same as the first way but shorter and can be inlined.
Мне кстати очень не хватает операций множества на словарях
Б
Не с двумя словарями, а со словарём и множеством ключей например
S
There are a lot of ways to merge two dicts:
1. Long but simple:
2. Unpacking (keys must be strings):
3. Unpacking again:
4.
In python 3.9, PEP-584 introduced the 5th way. Meet the
Basically, that's the same as the first way but shorter and can be inlined.
1. Long but simple:
merged = d1.copy()
merged.update(d2)
2. Unpacking (keys must be strings):
merged = {**d1, **d2}3. Unpacking again:
merged = dict(d1, **d2)
4.
collections.ChainMap. Result isn't dict but so.In python 3.9, PEP-584 introduced the 5th way. Meet the
| operator for dict!merged = d1 | d2
Basically, that's the same as the first way but shorter and can be inlined.
А автор Грам?
Не могу его найти в чате, хотел спросить, почему он написал, что мержить распаковкой можно словари с ключами-строками
➜
Не могу его найти в чате, хотел спросить, почему он написал, что мержить распаковкой можно словари с ключами-строками
➜
python3.7
Python 3.7.7 (v3.7.7:d7c567b08f, Mar 10 2020, 02:56:16)
[Clang 6.0 (clang-600.0.57)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> a = {1:2}
>>> b = {3:4}
>>> c = {**a, **b}
>>> c
{1: 2, 3: 4}S
There are a lot of ways to merge two dicts:
1. Long but simple:
2. Unpacking (keys must be strings):
3. Unpacking again:
4.
In python 3.9, PEP-584 introduced the 5th way. Meet the
Basically, that's the same as the first way but shorter and can be inlined.
1. Long but simple:
merged = d1.copy()
merged.update(d2)
2. Unpacking (keys must be strings):
merged = {**d1, **d2}3. Unpacking again:
merged = dict(d1, **d2)
4.
collections.ChainMap. Result isn't dict but so.In python 3.9, PEP-584 introduced the 5th way. Meet the
| operator for dict!merged = d1 | d2
Basically, that's the same as the first way but shorter and can be inlined.
Кажется, он перепутал с вызовом dict
>>> dict(**a, **b)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: keywords must be stringsБ
Кажется, он перепутал с вызовом dict
>>> dict(**a, **b)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: keywords must be stringsДа, как рах хотел написать
E
А автор Грам?
Не могу его найти в чате, хотел спросить, почему он написал, что мержить распаковкой можно словари с ключами-строками
➜
Не могу его найти в чате, хотел спросить, почему он написал, что мержить распаковкой можно словари с ключами-строками
➜
python3.7
Python 3.7.7 (v3.7.7:d7c567b08f, Mar 10 2020, 02:56:16)
[Clang 6.0 (clang-600.0.57)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> a = {1:2}
>>> b = {3:4}
>>> c = {**a, **b}
>>> c
{1: 2, 3: 4}Автор @pushtaev
DB
S
E
понятно :)
Б
Не с двумя словарями, а со словарём и множеством ключей например
Б
Ужасно же
AK
There are a lot of ways to merge two dicts:
1. Long but simple:
2. Unpacking (keys must be strings):
3. Unpacking again:
4.
In python 3.9, PEP-584 introduced the 5th way. Meet the
Basically, that's the same as the first way but shorter and can be inlined.
1. Long but simple:
merged = d1.copy()
merged.update(d2)
2. Unpacking (keys must be strings):
merged = {**d1, **d2}3. Unpacking again:
merged = dict(d1, **d2)
4.
collections.ChainMap. Result isn't dict but so.In python 3.9, PEP-584 introduced the 5th way. Meet the
| operator for dict!merged = d1 | d2
Basically, that's the same as the first way but shorter and can be inlined.
Basically, that's the same as the first
Точно? Оно аффектит первый словарь? Чет сомнительно
Точно? Оно аффектит первый словарь? Чет сомнительно
Б
Basically, that's the same as the first
Точно? Оно аффектит первый словарь? Чет сомнительно
Точно? Оно аффектит первый словарь? Чет сомнительно
Точно
AK
А, там copy. Сорян