KV
Haskell> (1 + 2) @Int
<interactive>:14:1: error:
* Cannot apply expression of type `a0'
to a visible type argument `Int'
* In the expression: (1 + 2) @Int
In an equation for `it': it = (1 + 2) @Int
Haskell> let three :: Num n => n ; three = 1 + 2 in three @Int
3
Да почему