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Size: a a a
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H
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select id,
status,
code,
LAG(code,1) OVER (
ORDER BY code
) prev_code,
LAG(code,1) OVER (
ORDER BY code
) prev_code,
LEAD(code,1) OVER (
ORDER BY code
) next_code,
LAG(status,1) OVER (
ORDER BY code
) prev_status
from test,
where status = 'OK'
and prev_status = 'neOK'
and code = prev_code
and code != next_code
```ЗА
H
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H
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H
A
A
С
S